PHP filter_input not working

Question

I have a PHP script that shows some server variables, the code is as following :

<?php
$FILTEREDHOST = filter_input(INPUT_SERVER,'HTTP_HOST');
$FILTEREDSELF = filter_input(INPUT_SERVER,'PHP_SELF');

$SERVERHOST = $_SERVER['HTTP_HOST'];
$SERVERSELF = $_SERVER['PHP_SELF'];

var_dump($FILTEREDHOST);
echo "</br>";
var_dump($FILTEREDSELF);
echo "</br>";
var_dump($SERVERHOST);
echo "</br>";
var_dump($SERVERSELF);

The result I get is :

NULL
string(9) "/test.php"
string(17) "www.mysite.com"
string(9) "/test.php"

Why $FILTEREDHOST is returning NULL ?

My PHP version is 5.5.16

Charlotte Dunois · Accepted Answer · 2014-09-07 13:46:41Z

1

HTTP_HOST is not set if the browser didn't send it.

'HTTP_HOST' Contents of the Host: header from the current request, if there is one.

http://php.net/manual/en/reserved.variables.server.php

answered Sep 7, 2014 at 13:46

Charlotte Dunois

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3 Comments

oussama kamal Over a year ago

why the browser sent it here :$SERVERHOST = $_SERVER['HTTP_HOST']; ??

Charlotte Dunois Over a year ago

I think it has to do with the strange side-effects of FastCGI. ch2.php.net/manual/en/function.filter-input.php#77307

oussama kamal Over a year ago

Well, you might be right, I used the suggested function in that link and I see the the SERVER variable content and the HTTP_HOST is present.

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