Removes and returns the first occurrence of the specified string in array using Java [duplicate]

Question

I am trying to delete from an array the first occurence, not all elements like the searched element The array is something like:

 String[] names = {"Becky", "Rosa", "Tina", "Jill", "Rosa", "Bill"};

And I want to be able to say remove(Rosa) and only find and remove the first element in the array named Rosa.

Might want to qualify what you mean by delete, and consider using a List. — C.B.
– C.B., Commented Sep 9, 2014 at 22:09
The same question is asked here: stackoverflow.com/questions/7940337/… — MrD
– MrD, Commented Sep 9, 2014 at 22:12
@djechlin: What about that array declaration is invalid syntax? — Makoto
– Makoto, Commented Sep 9, 2014 at 22:16

Jay · Accepted Answer · 2014-09-11 01:02:32Z

1

So you might want to consider using an Arraylist for dynamic removal and resizing

import java.util.ArrayList;


ArrayList<string> persons = new ArrayList<string>();
persons.add("Becky");
//... adding in people to the list

//then if you want to remove  someone name "becky"
persons.removeall.(collection.singleton("Becky"))

edited Sep 11, 2014 at 1:02

answered Sep 9, 2014 at 22:15

Jay

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6 Comments

Christopher Smith Over a year ago

Use a while loop to remove all Beckys `while(persons.remove("Becky");

Jay Over a year ago

don't have to use a while, can just use removeall

Christopher Smith Over a year ago

But then you have to deal with collections.

Jay Over a year ago

Not like thats a big deal removeall.(collection.singleton("Becky"))

Christopher Smith Over a year ago

Too-shay, I have never done Collections before so I had no idea, you should change your post to removeAll instead of while

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