Python error "'int' object is not callable"

Question

I wrote some code for a program that gives me the values of a sequence I defined as a function, f(x), but when I run it a error pops saying 'int' object is not callable". Does anyone know how to solve the problem?

def f(x):
    if x%2==0:
        return x/2
    else:
        return 3*x+1
limite=int(input("parar en: "))   
x=int(input("a1: "))
print(x)
n=1
while n<=limite:
    f=f(x)
    print(f)
    n=n+1
print("fin")

Daniel Roseman · Accepted Answer · 2014-09-11 20:33:47Z

5

You're reassigning f within the while loop, to the result of calling f(x), which indeed an integer. So, the second time through the loop, f is an integer rather than a function.

I suspect you simply meant:

x = f(x)
print x

answered Sep 11, 2014 at 20:33

Daniel Roseman

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1 Comment

Ihor Pomaranskyy Over a year ago

Javier, also you definitely should to take a look on PEP-0008 document: it defines the coding guidelines, which are respecting by all Python programmers.

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