Unable to click link using selenium webdriver in python

Question

I am trying to click on the link shown below:

<a class="user" href="/Kevin-Rose" action_mousedown="UserLinkClickthrough" id="__w2_L73qRYl_link" 
target="_blank">
         <span class="matched_term">Kevin Rose</span>
</a>

I tried using following code:

 user = driver.find_element_by_xpath("//a[@class='user'][1]")
 user.click()

I got following error:

ElementNotVisibleException: Message: u'Element is not currently visible and so may not be interacted with' ; Stacktrace:

How can I solve this problem?

enter image description here

Are you sure the link is visible? Can you provide us with a link to the website under test? — alecxe
– alecxe, Commented Sep 12, 2014 at 15:24
Do you want to click any particular link ? Can you post screenshot by highlighting required link to click? — Santoshsarma
– Santoshsarma, Commented Sep 12, 2014 at 15:39

Willem van Ketwich · Accepted Answer · 2017-07-21 00:25:44Z

1

The problem is that you are finding the element while it is not yet there. Wait for it.

Here's the complete code, from logging in, search to following the first Kevin Rose link:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC


URL = "http://www.quora.com"
EMAIL = 'your email here'
PASSWORD = 'your password here'

driver = webdriver.Chrome()  # can be webdriver.Firefox() in your case
driver.get(URL)
wait = WebDriverWait(driver, 10)

# login
form = driver.find_element_by_class_name('regular_login')
username = form.find_element_by_name('email')
username.send_keys(EMAIL)

password = form.find_element_by_name('password')
password.send_keys(PASSWORD)

login_button = form.find_element_by_xpath('//input[@type="submit" and @value="Login"]')
login_button.click()

# search
search = wait.until(EC.presence_of_element_located((By.XPATH, "//form[@name='search_form']//input[@name='search_input']")))
search.send_keys('Kevin Rose')
search.send_keys(Keys.ENTER)

# follow the link
link = wait.until(EC.presence_of_element_located((By.LINK_TEXT, "Kevin Rose")))
link.click()

edited Jul 21, 2017 at 0:25

Willem van Ketwich

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answered Sep 12, 2014 at 15:51

alecxe

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2 Comments

Siddhesh Over a year ago

It worked perfectly.Thanks a lot. I was using python shell and executing the code line by line,then why wait is required?

alecxe Over a year ago

@Siddhesh since quora loads the page asynchronously, not all the elements are there after the initial data comes. Waits is a pretty neat technique comparing to lots of time.sleep() calls.

Santoshsarma · Accepted Answer · 2014-09-12 15:57:12Z

0

Try with below locators

Xpath : "//span[text()='Kevin Rose']"

cssSelector : "a[href*='Kevin-Rose'] > span"

Edit-I

Here is the Xpath to click on Profile name Kevin Rose

"//div[contains(.,'Profile:') and contains(@class,'photo')]/span/a//span[text()='Kevin Rose']"

edited Sep 12, 2014 at 15:57

answered Sep 12, 2014 at 15:23

Santoshsarma

5,6671 gold badge26 silver badges39 bronze badges

3 Comments

Siddhesh Over a year ago

It didn't give any error but i am on the same page. There are multiple instances of "Kevin Rose" may be that is the reason. My pointer was in the search box when i selected the element. I will try with different indexes and check if it works, but thats again a tedious task.

Santoshsarma Over a year ago

Do you want to click any particular link ? Can you post screenshot by highlighting required link to click?

Santoshsarma Over a year ago

I've edited my answer and added xpath. Try with that and let me know.

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