Faster way to parse a JSON String in android

Question

I'm using this method to parse a JSON string, but it is too slow... is there a better way to do it? Thanks

synchronized private void parseCategories(String response){

    try{
        JSONArray categoriesJSONArray = new JSONArray (response);


        // looping through All Contacts
        for(int i = 0; i < categoriesJSONArray.length(); i++){
            JSONObject currentCategory = categoriesJSONArray.getJSONObject(i);

            String label="";
            String categoryId="";


            // Storing each json item in variable
            if(currentCategory.has("label"))
                label = currentCategory.getString("label");


            if(currentCategory.has("id"))
                categoryId = currentCategory.getString("id");

            if(
               label!=null &&
               categoryId!=null
              )
            {
                Category toAdd = new Category(categoryId, label);
                categories.add(toAdd);
            }

        }

        //Alphabetic order
        Collections.sort(
                categories,
                new Comparator<Feed>() {
                    public int compare(Feed lhs, Feed rhs) {
                        return lhs.getTitle().compareTo(rhs.getTitle());
                    }
                }
        );

        Intent intent = new Intent("CategoriesLoaded");
        LocalBroadcastManager.getInstance(mAppContext).sendBroadcast(intent);


    }catch (JSONException e) {
        e.printStackTrace();
    }

}

Have you tried using GSON? I am not sure if it is faster but it much more convinient — hoomi
– hoomi, Commented Sep 13, 2014 at 10:53
You are setting label="" and categoryId="" so there is no way they can be null. So don't you end up adding a lot of categories with "" as label and id? — MTilsted
– MTilsted, Commented Sep 13, 2014 at 10:57

Darshan Lila · Accepted Answer · 2014-09-13 11:49:58Z

1

Here's try following code to start with. You would need Gson library for it.

Gson gson=new Gson();
MyBean myBean=gson.fromJson(response);

Note: Here MyBean class contains the fields present in you json string for e.g. id, along with getter and setters. Rest of all is handled by Gson.

Here's a quick demo.

import com.google.gson.annotations.SerializedName;

public class Box {

  @SerializedName("id")
  private String categoryId;

  // getter and setter
}

Say you JSON looks as following:

{"id":"A12"}

You can parse it as follows:

class Parse{
 public void parseJson(String response){
  Gson gson=new Gson();
  Box box=gson.fromJson(response,Box.class);
  System.out.println(box.getCategoryId());
 }
}

Output :

A12

For more on Gson visit here

edited Sep 13, 2014 at 11:49

answered Sep 13, 2014 at 11:21

Darshan Lila

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6 Comments

Usi Usi Over a year ago

Thanks, but how Can I do if the parameter "id" in the json string must inserted in the String "id_cat" of the class... is there a way to do that?

Darshan Lila Over a year ago

Use annotations for them. You can specify json key in class's field annotation.

Usi Usi Over a year ago

Thanks, It help. But I have a class called Feed and 2 others that inherits from it... Is there a way to create different annotation for the subclasses?

Darshan Lila Over a year ago

Yes you can do that (provide different annotations)

Usi Usi Over a year ago

Thanks, I can't find an example of different annotations. Can you post an example? Feed has got the ID tag Subscriptions ID tag must be for example id_sub Categories ID tag must be for example id_cat

|

Bob · Accepted Answer · 2014-09-13 10:57:57Z

1

Use GSON library. You can convert your object to json string like the following example:

MyClass MyObject;
Gson gson = new Gson();
String strJson = gson.toJson(MyObject);

answered Sep 13, 2014 at 10:57

Bob

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