Not able to execute linux command using processBuilder

Question

I using Processbuilder as follows:

            List<String> args = initArgs();
            ProcessBuilder pb = new ProcessBuilder(args);
            tdmServerProcess = pb.start();

            handleInfoLog(tdmServerProcess.getInputStream());
            handleErrorLog(tdmServerProcess.getErrorStream());

In the initArgs method I am setting the linux commands I want to execute, as follows:

args.add("java -version");
args.add(javaHome + File.separator + "bin" + File.separator + "java");

first command is getting executed successfully. But second is failing with following error:

/opt/java7/bin/java: cannot execute binary file

though i have execute permission, following are permission bits:

-r-xr-xr-x

I am able to execute the same command from terminal.

alonana · Accepted Answer · 2014-09-16 07:40:59Z

2

The error "cannot execute binary file" means that the java file is not valid. Maybe the 'java -version' is actually running java from another location in your path, and the /opt/java7/bin/java is not valid. Try running the '/opt/java7/bin/java' manually, and check the result. Check also the location of java in your path by running which java using the same user that your are running your java code with.

answered Sep 16, 2014 at 7:40

alonana

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3 Comments

Arun Dixit Over a year ago

I am able to execute following command -bash-4.2$ /opt/java7/bin/java -version java version "1.7.0.09" Java(TM) SE Runtime Environment (build 1.7.0.09-jinteg_2014_02_03_13_09-b00) Java HotSpot(TM) 64-Bit Server VM (build 24.51-b03-jre1.7.0.09-rc1, mixed mode)

isalgueiro Over a year ago

Then your code is running in a 32bit JVM. cannot execute binary file is usually caused for trying to run wrong binnaries for your arch. Just try which java to see what JVM are you really running.

Arun Dixit Over a year ago

which java gives me following: -bash-4.2$ which java /opt/java7/bin/java

GreyBeardedGeek · Accepted Answer · 2014-09-16 07:54:13Z

0

You apparently are trying to execute two separate commands, first "java -version" and then "/opt/java7/bin/java" ?

That's not how it works. Rather, all of the arguments are appended and one process is started. In your case, the command is "java -version /opt/java7/bin/java"

Try running that at the console - I'm betting that you get the same error.

answered Sep 16, 2014 at 7:54

GreyBeardedGeek

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1 Comment

Arun Dixit Over a year ago

you are rite. its getting executed as java -version /opt/java7/bin/java. I tried the same on console. following is the output: -bash-4.2$ java -version /opt/java7/bin/java java version "1.7.0.09" Java(TM) SE Runtime Environment (build 1.7.0.09-jinteg_2014_02_03_13_09-b00) Java HotSpot(TM) 64-Bit Server VM (build 24.51-b03-jre1.7.0.09-rc1, mixed mode)

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