Let's say I have an array :
var arr = [1,2,3,4,5];
and I'm looping them with jQuery.each:
$(arr).each(function(index, value){
if (somethingIsTrue){
// Based on if "somethingIsTrue" I want to remove this particular item from the array at this point
}
});
How can I achieve this?
var arr = [1, 2, 3, 4, 5, 6, 6, 7, 8, 9, 10, 11, 12];
var arr1 = [] //make a separate array to store numbers fulfilling specified condition
$.each(arr,function(i,v){
if(somethingIsTrue){
arr1.push(v) //fill second array with required numbers fulfilling specified condition
}
});
OR
var arr = [1,2,2,2,3,4,5,5,5,6,7,8];
var filteredarr = $.map(arr,function (value,index) {
return (somethingIsTrue ? value : null)
});
'filteredarr' will be a another array having numbers satisfying the condition.
OR
Try .splice() as shown :
var arr = [1,2,3,4,5];
$(arr).each(function(index, value){
if(somethingIsTrue){
arr.splice(index,1)
}
});
OR
$.each(arr,function(i,v){
if(somethingIsTrue){
var i1 = arr.indexOf(v);
arr.splice(i1,1);
}
});
NOTE :- Last two answers will work absolutely fine if array do not contains repeating numbers(as questioner specified in question) and first two answers will work in any scenario.
$(arr) with an array of numbers. Also, even if it works, I think it's not a good idea to remove elements from an array while you are iterating through it.
$(arr), when there's an $(arr) in your code, plain as day. On that point, your post is incontrovertibly incorrect. Aside from that, anyone has the prerogative to downvote answers that are using bad practices, and removing elements from an array while iterating through it is a bad practice.There are a number of problems with the way you're trying to go about this. You shouldn't use $(arr) on an array of numbers, and you shouldn't remove elements from an array while you are iterating through it. That's a surefire recipe for buggy code.
Instead of jQuery and each(), you should use Array.prototype.filter (you can also use $.grep() if you need to support older browsers or absolutely want to use jQuery):
var filtered = arr.filter(function (value) {
return !somethingIsTrue;
});
After this is called, filtered will be an array containing all the items where somethingIsTrue is not true (which is what I think you are asking for).
As stated above, jQuery each is not the tool to use here, but in general you should only use $(arr) when arr contains only DOM elements. To iterate over an ordinary array in jQuery, use $.each(arr, callback).
try this fiddle, http://jsfiddle.net/devools/35aysq6t/
var arr = [1, 2, 3];
$(arr).each(function (index, value) {
if (value = 2) {
arr = jQuery.grep(arr, function(value) {
return value != 2;
});
}
});
$(arr).each(function (index, value) {
$('.array').append(value + ',');
});
if (value = 2) will always execute its body. Also, this seems like a rather convoluted (and incorrect) way to accomplish this.
poponly removes the last element in the array.