jQuery push() returns error "undefined is not a function"

Question

this code gives me an error when submitting he form "undefined is not a function in line 21" and I don't know why

$.fn.serializeObject = function()
{
    var o = {};
    var a = this.serializeArray();
    $.each(a, function() {
        if (o[this.name] !== undefined) {
            if (!o[this.name].push) {
                o[this.name] = [o[this.name]];
            }
            o[this.name].push(this.value || '');
        } else {
            o[this.name] = this.value || '';
        }
    });
    return o;
};

$("form[name=dForm]").submit(function(ev){
        ev.preventDefault();
        var data = $(this).serializeObject();
        data.push({name:"bonjour",value:bonjour});

 // do something here ...

})

or it must be an array not an object?

yes, and I dont know how to make it in array. because I have a multiple forms with same selector — deception
– deception, Commented Sep 17, 2014 at 12:55

Quentin · Accepted Answer · 2014-09-17 12:55:51Z

3

serializeObject returns o which is defined at the top of the function as {}.

push is a method of Array objects, not plain objects. It puts an item onto the end of an array.

Plain objects are unordered. There isn't an "end" to put the item onto, so it doesn't make sense for there to be a push method.

You, presumably, want to just create a new property with a given name and value.

data.push({name:"bonjour",value:bonjour});

should be

data.bonjour = bonjour;

answered Sep 17, 2014 at 12:55

Quentin

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1 Comment

Quentin Over a year ago

@Shashank — What does that have to do with anything? This is about assigning a new value, not reading an existing one.

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