Passing an Array as Arguments NOT user function, in PHP

Question

I have the following code:

$bin = "\x04\x00\xa0\x00\x04\x00\xa0\x00";
$unpack_data = unpack("C*", $bin);
$arr = array($unpack_data[1], $unpack_data[2], $unpack_data[3]);

How can I pass an array $arr to a pack() function? The only thing that I can make:

$res = pack("C*", $unpack_data[1], $unpack_data[2], $unpack_data[3]);

but the length and content of the array are getting in the course of the program.

deceze · Accepted Answer · 2014-09-19 07:07:54Z

3

Like this:

call_user_func_array('pack', array_merge(['C*'], $unpack_data))

answered Sep 19, 2014 at 7:07

deceze♦

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Comments

sectus · Accepted Answer · 2014-09-19 07:13:39Z

2

pack('C*', ...$unpack_data);

answered Sep 19, 2014 at 7:13

sectus

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Davan Polampalli · Accepted Answer · 2014-09-19 07:13:11Z

0

$res = pack('C*',$arr)

//hope this might help you

answered Sep 19, 2014 at 7:13

Davan Polampalli

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