Converting object to array (angularjs and typeahead)

Question

Let's say I have an object that looks like this: {"1": "2", "3": "4"}

I don't have direct access to this data, so when I bring it in via ajax how can I convert it to an array? Like so: [{"1": "2"}, {"3": "4"}]

PS: I'm using this output data in an angular-ui typeahead which dislikes objects and only likes strings.

So you want to turn an object into an array of objects with each element representing a property?' — sma
– sma, Commented Sep 24, 2014 at 17:14
u can try this way $scope.arrayList = @Html.Raw(Json.Encode(Object)); — X-Coder
– X-Coder, Commented Jun 17, 2015 at 7:12

SteveD · Accepted Answer · 2014-09-24 17:25:14Z

9

Here's a snippet:

var inputObj = {'1': '2', '3': '4'};
var output = [];
for (var key in inputObj) {
  // must create a temp object to set the key using a variable
  var tempObj = {};
  tempObj[key] = inputObj[key];
  output.push(tempObj);
}

console.log(output);

Hope that helps!

answered Sep 24, 2014 at 17:25

SteveD

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5 Comments

matenji Over a year ago

What does the [key] refer to?

SteveD Over a year ago

When you use a for loop to iterate over an object, it actually iterates over the keys (as in key/value pairs) of the object as the index. You can then use the key to get the value from the object using the index notation myObject[key]. For example, for an object {'myKey': 'myValue'}, you can get the key from the object via myObject['myKey']. Does that make sense?

SteveD Over a year ago

@matenji: I made a slight typo in that comment -- I meant: For example, for an object {'myKey': 'myValue'}, you can get the value from the object via myObject['myKey'].

matenji Over a year ago

I get it, so what if you just want the value of myValue?

SteveD Over a year ago

@matenji: In this example, the value of the object is "myValue", so you would get it by using myObject['myKey']. That example is a little confusing because the values look like variable names. Here's a less confusing example: var employee = {'firstName': 'Steve', 'lastName': 'Davis'}; console.log('First name is: ' + employee['firstName']); That would print "First name is Steve".

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