Append Character to String in Swift

Question

I'm trying to append Character to String using "+=", but It doesn't really work. Once I tried with append method, it works. I just wonder why it is. The compiler says "string is not identical to Unit8".

let puzzleInput = "great minds think alike"
var puzzleOutput = " "
for character in puzzleInput {

    switch character {
        case "a", "e", "i", "o", "u", " ":
        continue

    default:
        // error : doesn't work
        puzzleOutput += character
        //puzzleOutput.append(character)
    }
}
println(puzzleOutput)

FYI, it will work if you make character a String first: puzzleOutput += String(character). — Mike S
– Mike S, Commented Sep 25, 2014 at 1:58

Community · Accepted Answer · 2020-06-20 09:12:55Z

3

20140818, Apple updated:

Updated the Concatenating Strings and Characters section to reflect the fact that String and Character values can no longer be combined with the addition operator (+) or addition assignment operator (+=). These operators are now used only with String values. Use the String type’s append method to append a single Character value onto the end of a string.

Document Revision History 2014-08-18

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Sep 25, 2014 at 1:53

jseanj

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3 Comments

Toshi Over a year ago

Thanks a lot. I tried out with puzzleOutput += "(character)". And it works.

jseanj Over a year ago

@Toshi puzzleOutput += "(\character)" should also work.

Toshi Over a year ago

oh yeah I meant puzzleOutput += "(\character)" . Thanks anyway!

Suragch · Accepted Answer · 2015-07-12 04:57:55Z

0

To append a Character to a String in Swift you can do something similar to the following:

var myString: String = "ab"
let myCharacter: Character = "c"
let myStringChar: String = "d"

myString += String(myCharacter) // abc
myString += myStringChar // abcd

answered Jul 12, 2015 at 4:57

Suragch

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Comments

monadis · Accepted Answer · 2016-04-08 06:41:52Z

0

Updated version

let puzzleInput = "great minds think alike"
var puzzleOutput = ""
for character in puzzleInput.characters {
  switch character {
  case "a", "e", "i", "o", "u", " ":
   continue
  default:
    puzzleOutput += String(character)
  }
}
print(puzzleOutput)
// prints "grtmndsthnklk"

answered Apr 8, 2016 at 6:41

monadis

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