Insert one bash script into another

Question

I have two bash scripts: main one and auxiliary.

Let's say main script is:

#!/bin/bash

echo "This is start of my main script"
./auxiliary.sh
echo "This is end of my main script"

and auxiliary one is:

cd some-folder
echo "This is file placed in some-folder by auxiliary script" > file1
cd ..
cd other-folder
echo "This is file placed in other-folder by auxiliary script" > file2

My goal is to execute lines in auxiliary script (or just text file) as if those lines were written directly in main script. So if, for example, I invoke auxiliary.sh from inside a loop or function, all lines of auxiliary.sh will be executed in that loop or function.

chepner · Accepted Answer · 2014-09-25 16:29:20Z

4

Use the . command (alternately available as source in bash):

echo "This is the start of my main script"
# . ./auxiliary.sh
source ./auxiliary.sh
echo "This is the end of my main script"

answered Sep 25, 2014 at 16:29

chepner

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Comments

user4079229 · Accepted Answer · 2014-09-25 16:32:54Z

0

You can insert the bash script into another using the . command.

answered Sep 25, 2014 at 16:32

user4079229

1 Comment

ohmu Over a year ago

Can you given an example?

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