format Strings in PHP

Question

I'm tying create a reference generator in PHP, and i need format String.

i tried this code but don't work

function refAll($db, $contest, $ano){
$newkey = getlastid($db)+1;
return sprintf("%s%d%1$05d",$contest, $ano, $newkey);}

the goal is the output sting formatted like this ABC201500000, where ABC2015 is fixed and the 00000 is always the value in $newkey but with 5 digits

in my code

$newkey = 1

$contest = ABC

$ano = 2015

and the output is always ABC201500000

Your problem is probably in getlastid() since that is what generates the value for $newKey which is not working. — John Conde
– John Conde, Commented Sep 25, 2014 at 16:48
the value of $newkey is correct, and if i forced a value sprintf("%s%d%1$05d",$contest, $ano, 1234), give me the same result — Goncalo Feliciano
– Goncalo Feliciano, Commented Sep 25, 2014 at 16:53
$05d? Shouldn't that be %05d? $05 means nothing to sprintf — Marc B
– Marc B, Commented Sep 25, 2014 at 16:54
"the goal is the output sting formatted like this ABC201500000" / "and the output is always ABC201500000". So it's working then? — Mike
– Mike, Commented Sep 25, 2014 at 16:57

Alejandro Arbiza · Accepted Answer · 2014-09-25 16:57:25Z

2

Try this:

sprintf("%s%d%05d",$contest, $ano, $newkey)

answered Sep 25, 2014 at 16:57

Alejandro Arbiza

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