Count function not working in PHP to find size of array

Question

$datas = array();

while($row = mysql_fetch_array($firstQueryResult)) {
    $phones["Id"] = $row['person_id'];
    $phones["Latitude"] = $row['lat'];
    $phones["Longitude"] = $row['lng'];
    $phones["Distance"] = $row['distance'];
    $phones["DateTime"] = $row['location_datetime'];
    $datas["mydata"][] = $phones;
}

echo "Count = ".count($datas); // always returning 1 while i have more than 1 recor
echo "Count = ".sizeof($datas); // always returning 1 while i have more than 1 record

Anyone can please help me.

If the parameter is not an array or not an object with implemented Countable interface, 1 will be returned. — Vimalnath
– Vimalnath, Commented Sep 26, 2014 at 6:32

Andy Gee · Accepted Answer · 2014-09-26 06:31:57Z

4

Try this

echo "Count = ".count($datas['mydata']);
echo "Count = ".sizeof($datas['mydata']);

answered Sep 26, 2014 at 6:31

Andy Gee

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Comments

Clément Malet · Accepted Answer · 2014-09-26 06:32:24Z

0

$datas has only 1 element -> "mydata".

You want to count the number of entries in mydata, so :

count($datas["mydata"]);

answered Sep 26, 2014 at 6:32

Clément Malet

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