How to allocate array of pointers to arrays

Question

int (**test)[4][4] = new ???[64];
for (int i = 0; i < 32; ++i)
{
    test[i] = new int[4][4][4];
}

I'm trying to create a "list" of pointers that will be initialized to NULL and then later assigned the address of a new multidimensional array of int. The for loop will (eventually) vary in number of iterations, anywhere from 0 to the full 64. I expect to end up with an array of pointers where some are valid and the rest are NULL. The problem is that I can't figure out the syntax for allocating this array of pointers. Basically, what could I put in place of those question marks?

possible duplicate of How do I declare a 2d array in C++ using new? — Cory Kramer
– Cory Kramer, Commented Sep 28, 2014 at 17:24
@Cyber - I understand how to allocate a multidimensional array on the heap, but I can't figure out the syntax for this particular case. — user4088508
– user4088508, Commented Sep 28, 2014 at 17:28

fredoverflow · Accepted Answer · 2014-09-28 17:30:48Z

1

In the name of readability, may I suggest using a typedef?

typedef int (*t)[4][4];
t* test = new t[64];

You will thank me next week when you have to maintain that horrible piece of code ;)

answered Sep 28, 2014 at 17:30

fredoverflow

265k101 gold badges403 silver badges680 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How to allocate array of pointers to arrays

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related