XML jQuery get multiple nodes with same name

Question

I have a part of an XML file that looks like this:

<paymentTypes>
<paymentType>type1</paymentType>
<paymentType>type2</paymentType>
<paymentType>type3</paymentType>
<paymentType>type4</paymentType>
</paymentTypes>

The thing is that I want to get it via ajax jQuery, but if I try this:

var paymentTypes = $(xml).find("paymentTypes").text()

the output will be type1type2type3type4.

What function should I use(built-in or should I write it) in order to get the results on separate lines?

Thanks!

UPDATE: In my XML file there are multiple items, each of them with their own entry.

what is the desired output? do you need an array of the text values — Arun P Johny
– Arun P Johny, Commented Sep 30, 2014 at 10:44
if so var paymentTypes = $(xml).find("paymentType").map(function(){return $(this).text()}).get() — Arun P Johny
– Arun P Johny, Commented Sep 30, 2014 at 10:44
@Matei_Radu should this output be in console or in page (with <br/> instead of \n)? — Regent
– Regent, Commented Sep 30, 2014 at 10:51

mfarouk · Accepted Answer · 2014-09-30 11:59:36Z

1

u can iterate over the result append to new string

var xml ='<paymentTypes><paymentType>type1</paymentType><paymentType>type2</paymentType><paymentType>type3</paymentType><paymentType>type4</paymentType></paymentTypes>';

var result = "";
$(xml).find('paymentType').each(function(i,v){
    result += $(v).text()+'\n';
});
console.log(result);

answered Sep 30, 2014 at 11:59

mfarouk

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