Javascript string.replace. Combining several .replace commands

Question

I am working on an assignment using javascript but I am stuck on a problem. When I try to join together several .replace commands i do not get the expected output. I do not use any libraries like Jquery.

var str = ('abc abc');
str = str.replace(/a/g, 'b').replace(/b/g, 'c');

alert(str);

With my code I get this output: ccc ccc. When I should get this: bcc bcc.

Can anyone see what I am doing wrong?

Best regards, a student from Norway :)

What you should get is exactly what you get. ;-) What you want to get might be different though. :-o — RobG
– RobG, Commented Oct 1, 2014 at 0:45

Donal · Accepted Answer · 2014-10-01 00:35:38Z

1

Like @elclarns said, switch the replace functions so you are replacing b with c first.

str = str.replace(/b/g, 'c').replace(/a/g, 'b');

answered Oct 1, 2014 at 0:35

Donal

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2 Comments

user2926446 Over a year ago

Thanks for the example! Can you explain why it is like that?

cbayram Over a year ago

@user2926446, because code above executes left to right. second replace gets called on the result of the first replace.

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