You have:
val array = new Array[Array[Cell]](height, width)
How do you initialize all elements to new Cell("something")?
Thanks, Etam (new to Scala).
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4 Answers
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scala> val (height, width) = (10,20)
height: Int = 10
width: Int = 20
scala> val array = Array.fill(height, width){ new Cell("x") }
array: Array[Array[Cell[java.lang.String]]] = Array(Array(Cell(x), Cell(x), ...
scala>
Comments
val array = Array.fill(height)(Array.fill(width)(new Cell("something")))
1 Comment
sepp2k
This is nicer than fromFunction, but it requires scala 2.8. Note that you can just use the two-dimensional version of fill:
Array.fill(height, width)(new Cell("something")).val array = Array.fromFunction((_,_) => new Cell("something"))(height, width)
Array.fromFunction accepts a function which takes n integer arguments and returns the element for the position in the array described by those arguments (i.e. f(x,y) should return the element for array(x)(y)) and then n integers describing the dimensions of the array in a separate argument list.
Comments
Assuming the array has already been created, you can use this:
for {
i <- array.indices
j <- array(i).indices
} array(i)(j) = new Cell("something")
If you can initialize at creation, see the other answers.
