How to decode JSON from Java REST API request?

Question

I'm sending data to an API from Java using POST.

What I'm trying to do is send a particular variable to the API in the POST request, and then use the value of it. But currently the value is empty. The API is definitely being called.

My Java looks like this:

String line;
StringBuffer jsonString = new StringBuffer();

try {
    URL url = new URL("https://www.x.com/api.php");
    String payload = "{\"variable1\":\"value1\",\"variable2\":\"value2\"}";

    HttpURLConnection connection = (HttpURLConnection) url.openConnection();

    connection.setDoInput(true);
    connection.setDoOutput(true);
    connection.setRequestMethod("POST");
    connection.setRequestProperty("Accept", "application/json");
    connection.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
    OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream(), "UTF-8");
    writer.write(payload);
    writer.close();

    BufferedReader br = new BufferedReader(new InputStreamReader(connection.getInputStream()));
    while ((line = br.readLine()) != null) {
        jsonString.append(line);
    }
    br.close();
    connection.disconnect();
}

This is based on: How to send Request payload to REST API in java?

Currently the value isn't being read correctly. Am I sending it correctly in Java? Do I have to do something to decode it?

pgiecek · Accepted Answer · 2014-10-01 20:16:57Z

1

The $_POST variable is not set for all HTTP POST requests, but only for specific types, e.g application/x-www-form-urlencoded.

Since you are posting a request containing JSON entity (application/json), you need to access it as follows.

$json = file_get_contents('php://input');
$entity= json_decode($json, TRUE);

edited Oct 1, 2014 at 20:16

answered Oct 1, 2014 at 20:09

pgiecek

8,2905 gold badges42 silver badges48 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Andreas Over a year ago

damn it you were faster xD take my medal!

pgiecek Over a year ago

Look at json_decode() documentation. The second parameter determines whether to return associative array. This should work $entity['variable1'].

user4080356 · Accepted Answer · 2014-10-01 20:07:41Z

0

You can try to use the following code instead of your String variable payload:

List<NameValuePair> payload = new ArrayList<NameValuePair>();

payload.add(new BasicNameValuePair("variable1", "value1");

That worked for me

answered Oct 1, 2014 at 20:07

user4080356

Collectives™ on Stack Overflow

How to decode JSON from Java REST API request?

2 Answers 2

2 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related