Parse json in jquery and java

Question

Hi i am trying to make code for parse json in jquery and command comes from java controller and i didn't get solution

urlAddCountry="countries/countrylist";
getAjaxCountry(urlAddCountry, CountryDetails, true,true);


function CountryDetails(res)
{
    alert(res);
}

function getAjaxCountry(urlAddCountry, func, isToken,isContentHeader)
{

    var url=serviceURL + urlAdd;
    $.ajax({
        url: url,
        type: "POST",
        //isasync: isAsync,
        contentType : "application/json",
        beforeSend:function(xhr){
            if(isContentHeader){
                xhr.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
            } 
            if(isToken){
                xhr.setRequestHeader("tokenId",sessionStorage.tokenID);
            }
        },
        success: function(res) {
            alert(res);
            func(res);
        },
        error : function(err) {
            func(err);
            alert("ERROR:STATUS- " + err.status + "; RESPONSETEXT- " + err.responseText + "; STATUSTEXT- " + err.statusText);
            //return null;
        }
    });

}

[{"entry_id":1,"countryName":"India","phoneCode":"91","countryCode":"IN","isBlackListedForPGTran":"0"},{"entry_id":2,"countryName":"Timor-Leste","phoneCode":"NULL","countryCode":"TL","isBlackListedForPGTran":"0"}]

Does the console log any errors? Please specify the problem. — user
– user, Commented Oct 2, 2014 at 8:16
for single rows it works but for multiple rows it gives following alert [object object] — Jahangir Ansari
– Jahangir Ansari, Commented Oct 2, 2014 at 8:17
Getting [object object] doesn't have to mean something bad. Try console.log(x) instead of alert(x). — Nebril
– Nebril, Commented Oct 2, 2014 at 8:19

T J · Accepted Answer · 2014-10-02 08:46:55Z

1

According to what i understood from comments, you can use JSON.stringify to stringify your json so that you can see it.

var jsonArray = [{"entry_id":1,"countryName":"India","phoneCode":"91","countryCode":"IN","isBlackListedForPGTran":"0"},{"entry_id":2,"countryName":"Timor-Leste","phoneCode":"NULL","countryCode":"TL","isBlackListedForPGTran":"0"}]

alert(JSON.stringify(jsonArray));

Parsing means, to convert a json string into an object. If you alert an object, you'll see corresponding structure like [object object] as you mentioned in comments.

answered Oct 2, 2014 at 8:46

T J

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2 Comments

Loki Over a year ago

Since when can you execute code snippets on stackoverflow? That's a nice feature. Thank you for that. +1 therefore

T J Over a year ago

@Loki see introduction and Stack snippets 2.0

Darshan Lila · Accepted Answer · 2014-10-02 08:45:23Z

0

Try following using jquery

var json = jQuery.parseJSON(res);
    $.each(json, function(k, v) {
        console.log(k+' :: '+v);
    });

While in Java you need to use Json Librabry.

For download visit this link and for tutorial visit this link.

answered Oct 2, 2014 at 8:45

Darshan Lila

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Comments

pomeh · Accepted Answer · 2014-10-02 08:50:42Z

0

You can use the following code in your success callback:

var json = $.parseJSON(yourjsondatahere);
$(json).each(function(i,val){
    $.each(val,function(k,v){
        console.log(k+" : "+ v);     
    });
});

edited Oct 2, 2014 at 8:50

pomeh

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answered Oct 2, 2014 at 8:16

sakir

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3 Comments

sakir Over a year ago

in your case yourjsondatahere =res

Jahangir Ansari Over a year ago

not working success: function(res) { var json = $.parseJSON(res); $(json).each(function(i,val){ $.each(val,function(k,v){ console.log(k+" : "+ v); }); }); func(res); },

Jahangir Ansari Over a year ago

SyntaxError: JSON.parse: unexpected character at line 1 column 2 of the JSON data

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