Adding values to PHP array using jQuery

Question

That's what I have: <a href="<?=$arItem["LINK"]?>"><?=$arItem["TEXT"]?></a>. <?=$arItem["LINK"]?> - it's an array, which contains some links. I need to add an extra hashtag parameter #nav-link to the end of each link. That's how I tried do it, but this code doesn't work:

<a id="likeLink" href=""><?=$arItem["TEXT"]?></a>
<script>
    $(document).ready(function () {
        $("#likeLink").attr("href", <?=$arItem["LINK"]?> + "#nav-link");
    });
</script>

I don't know PHP quite well, but I think I need to add new array and return there all necessary links with hashtag and use this array in href.

Thanks for help!

Note sure it helps but I think it should be $("#likeLink").attr("href", "<?=$arItem["LINK"]?>#nav-link"); — nicolas
– nicolas, Commented Oct 2, 2014 at 20:19
@nicolas Unfortunately the result is the same, after second click I get only last element of the array — Mia
– Mia, Commented Oct 2, 2014 at 20:25
@Sean Yes, but it works well in this variant <a href="<?=$arItem["LINK"]?>"><?=$arItem["TEXT"]?></a> — Mia
– Mia, Commented Oct 2, 2014 at 20:26
It sounds like you might have an id issue. ids are supposed to be UNIQUE, so if this is in a loop you will have n number of id="likeLink". jQuery/javascript will not know which $("#likeLink") you are linking to. — Sean
– Sean, Commented Oct 2, 2014 at 20:32

Matthias · Accepted Answer · 2014-10-02 20:20:20Z

1

You have to give your php to javascript into a javascript string:

$("#likeLink").attr("href", "<?=$arItem["LINK"]?>#nav-link");

answered Oct 2, 2014 at 20:20

Matthias

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Cody Brumfield · Accepted Answer · 2014-10-02 20:19:33Z

0

It's hard to say without knowing more but it looks like you need quotes around the link on this line:

$("#likeLink").attr("href", "<?=$arItem["LINK"]?>" + "#nav-link");

answered Oct 2, 2014 at 20:19

Cody Brumfield

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4 Comments

Mia Over a year ago

Unfortunately the result is the same, after second click I get only last element of the array

Cody Brumfield Over a year ago

Does it work if you just put the code in PHP? $("#likeLink").attr("href", "<?php echo $arItem["LINK"].'#nav-link'; ?>");

Cody Brumfield Over a year ago

There's no reason it would be any different. I'm just curious if there's some code we can't see that's causing the issue.

nicolas Over a year ago

I'm sure there are guys here hefty enough to fix bugs in code that they can't see :)

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