Conditional not passing in batch script

Question

I've got a pretty simple batch script, but for some reason the conditional isn't working like I'm expecting:

SET RIG=%1
IF /I RIG==Polar (
    SET SQLSERVER=SQL01
    SET MONITOR=SQL02
    SET TESTSETTING="test"
    SET TESTCONTAINER="test2 
) ELSE ( 
    ECHO Your input was %1.
)

When I pass the following command: testrun.bat Polar I get the ECHO statement returned: Your input was Polar."

I've tried putting the %1 in quotations, messing with the way parentheses are laid out, and I've reviewed ss64.com's syntax for batch script IF statements, but I just can't figure this one out.

Just saw that in the answer below. I feel dumb, because I use variables elsewhere in this same script. — Sean Long
– Sean Long, Commented Oct 6, 2014 at 20:15

Magoo · Accepted Answer · 2014-10-06 20:11:51Z

1

RIGNAME is never going to be equal to Polar

Now you could try assigning the value to rigname rather than rig.

Even then, yu'd need to compare %rigname% to Polar to access the content of rigname rather than the string RIGNAME.

answered Oct 6, 2014 at 20:11

Magoo

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1 Comment

Sean Long Over a year ago

Holy crap. I use variables all over the place elsewhere in this same script, but somehow missed that. Beautiful, thanks. That makes perfect sense. Also the Rigname/Rig thing was just a typo on my part, in writing this. I'll fix that in the question.

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