Serializing a JSON string as JSON in Scala/Play

Question

I have a String with some arbitrary JSON in it. I want to construct a JsObject with my JSON string as a JSON object value, not a string value. For example, assuming my arbitrary string is a boring {} I want {"key": {}} and not {"key": "{}"}.

Here's how I'm trying to do it.

val myString = "{}"
Json.obj(
  "key" -> Json.parse(myString)
)

The error I get is

type mismatch; found :
  scala.collection.mutable.Buffer[scala.collection.immutable.Map[String,java.io.Serializable]]
  required: play.api.libs.json.Json.JsValueWrapper

I'm not sure what to do about that.

Dragisa Krsmanovic · Accepted Answer · 2014-10-08 00:03:44Z

2

"{}" is an empty object.

So, to get {"key": {}} :

Json.obj("key" -> Json.obj())

Update:

Perhaps you have an old version of Play. This works under Play 2.3.x:

scala> import play.api.libs.json._
scala> Json.obj("foo" -> Json.parse("{}"))
res2: play.api.libs.json.JsObject = {"foo":{}}

edited Oct 8, 2014 at 0:03

answered Oct 7, 2014 at 6:17

Dragisa Krsmanovic

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3 Comments

Jeffery Grajkowski Over a year ago

Nope, sorry. That was just an example for my arbitrary string.

Dragisa Krsmanovic Over a year ago

Sorry. I didn't understand your question then.

Jeffery Grajkowski Over a year ago

Huh. So in describing my problem I simplified out a detail I thought wasn't important but was. For some unknown reason I was actually doing Json.obj("foo" -> Map("bar" -> Json.parse("{}"))) when I should be doing Json.obj("foo" -> Json.obj("bar" -> Json.parse("{}"))). Your answer helped me reevaluate my assumptions so thank you for the help!

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