Javascript variable redundance

Question

I have a simple javascript function like this:

function wrapVar (passVar) {
    var option = {
        varValue: passVar,
        hide: true,
        params: { ..otherparams.. }
        };
    return option;
}

Eclipse and Aptana validation says that the local variable 'option' is redundant. But the meaning of "redundancy" in this case is not clear to me, what should i do to avoid it?

not sure you should necessarily avoid that. i think its personal preference and also not something that jshint would pick up. — go-oleg
– go-oleg, Commented Oct 7, 2014 at 17:48
Sometimes they hint at redundancy when nothing is wrong with the code itself — Petro
– Petro, Commented Oct 7, 2014 at 17:49

Oriol · Accepted Answer · 2014-10-07 17:47:38Z

5

Probably, it means you can use the equivalent

function wrapVar (passVar) {
    return {
        varValue: passVar,
        hide: true,
        params: { ..otherparams.. }
    };
}

answered Oct 7, 2014 at 17:47

Oriol

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1 Comment

Plastic Over a year ago

Absolutely true, it was just an optimization tip! the code was already running but i had desire to understand.. Now it's clear, thanks!!

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