How do I execute the following command getting filenames without paths?
So, literally, what the command says, "name-only" - not the file paths, just the file names.
git diff --name-only <commit> <commit>
1 Answer
AFAIK this is not provided by git since this is a pretty unusual requirement. For example my first try in my repository yielded about a dozen lines, each saying pom.xml because I just created a new version.
You can use a small script though. basename is your friend here.
I like xargs so I'd do it like this
git diff --name-only <commit> <commit> | xargs -n1 basename
This will fail if git diff provides no output.
Or for a loopy version
for s in `git diff --name-only <commit> <commit>` ; do basename $s ; done
7 Comments
Everlight
Didn't work: basename: missing operand. Also, I can't use bash.
Chris
@Everlight, if you can't use bash what can you use? Pretty much any shell will let you do something like this. Are you on Windows without
basename? You should probably add any such constraints to your question.Everlight
I'm using RHEL 5.7. So, anything within the Linux Terminal.
musiKk
@Everlight If you used the first version, this means there was no output from
git diff. This version also has no particular dependencies on bash.Everlight
By the first version, I assume you mean your first suggestion, which gave me the output, "basename: missing operand <new line> Try `basename --help' for more information." which repeated for each line in the output. So, there was output. If it has no dependency on bash then I assume its my version of basename: 5.97 is the problem.
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for i in `git diff --name-only <commit> <commit>` ; do basename $i ; doneREADME.txtfiles in different subdirectories? Why do you want to ignore the paths?README.txtfile once. From my comment below, "My manager is content with the file paths included, I assumed he didn't want them, so I panicked and made this question"