iterate over array using shell scripting and print it using php

Question

i'm learning the shell scripting using php

shell.sh

`#!/bin/bash

    BASEDIR=$(dirname $0)
    echo "BASE DIRECTOY $BASEDIR"           ## get base directory
    echo "PRESENT WORKING DIRECTORY $PWD"   ## get present working directory

    declare arr="`dir`"
    echo $arr

   for i in $arr
   do 
       echo $i
   done`

And i'm executing this shell script using php script

phpshell.php

`error_reporting(1);
    $output = shell_exec('sh shell.sh');
    echo $output;`

So when i'm echoing $arr in shell script, its working fine but when i applying for loop on same array in shell script, it's not printing file names

output

BASE DIRECTOY .
PRESENT WORKING DIRECTORY /cygdrive/c/wamp/www/shell
Copy\ of\ shell.sh htaccess new phpshell.php shell.sh

i tried all answers from stackoverflow and internet but no one solution is working. i'm running this code on wampserver and windows xp sp2. Also i installed a cygwin utility. i think there is no problem with cygwin

Any help would be greatly appreciated....

user4129403 · Accepted Answer · 2014-10-14 00:08:12Z

1

In phpshell.php, start by changing

$output = shell_exec('sh shell.sh');

to

$output = shell_exec('bash shell.sh');

The old Bourne shell (sh) doesn't understand 'declare'. I guess you got the error message

shell.sh: declare: not found

Another way to solve it is to remove declare from shell.sh.

(Your listings look a bit odd. Why do you frame all code with back-ticks?)

answered Oct 14, 2014 at 0:08

user4129403

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