Nginx returns a 404 for URLs like index.php/some/path

Question

Nginx returns a 404 when I query for an URL with a "path info" appended after the script name, e.g. http://example.com/index.php/hello.

Here is my config:

server {
    listen  80;
    root    @PROJECT_ROOT@/;
    index   index.php index.html;

    location ~ \.php$ {
        fastcgi_pass    unix:@PHP_FPM_SOCK@;
        include fastcgi_params;
        fastcgi_read_timeout 300s;
    }
}

I don't get why \.php$ doesn't match that URL, and I've tried searching for similar problems but can't find anything useful.

The pattern \.php$ is forcing nginx to match only URLs ending with .php. Why dont you a look on how popular frameworks arrange this setup like Symfony2? symfony.com/doc/current/cookbook/configuration/… — softius
– softius, Commented Oct 15, 2014 at 5:59

dev0z · Accepted Answer · 2014-10-15 06:31:55Z

2

Use

location ~ ^.+.php {

fastcgi_split_path_info ^(.+?.php)(/.*)$;

to match a .php in the uri split the parameters

answered Oct 15, 2014 at 6:31

dev0z

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1 Comment

dgatwood Over a year ago

That matches too broadly—on any character followed by "php". You need backslashes before literal periods.

dgatwood · Accepted Answer · 2016-03-19 21:25:36Z

1

This works for me:

location ~ \.php {
    # Split the path appropriately
    fastcgi_split_path_info ^(.+?\.php)(/.*)$;

    # Work around annoying nginx "feature" (https://trac.nginx.org/nginx/ticket/321)
    set $path_info $fastcgi_path_info;
    fastcgi_param PATH_INFO $path_info;

    # Make sure the script exists.
    try_files $fastcgi_script_name =404;

    # Configure everything else.  This part may be different for you.
    fastcgi_pass localhost:9000;
    fastcgi_index index.php;
    fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
    include fastcgi_params;
}

answered Mar 19, 2016 at 21:25

dgatwood

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