@Sam Battat's answer works too, but for a simple snippet of code that works on any year when called you could try this:
var thisDay = new Date();
var thisYear = thisDay.getYear();
var feb29th = new Date(thisYear, 1, 29);
var febDays = ((feb29th.getMonth() === 1) ? 29 : 28);
var dayCounts = [31,febDays,31,30,31,30,31,31,30,31,30,31];
Notes:
- The number of days is hard coded for all months except February since they don't change
- The
feb29th variable above will actually become March 1st on years that don't have 29 days (e.g. non-leap years) and thus the month won't be "1"... defaulting the number of days back to 28
Update:
After running this perf test http://jsperf.com/leap-year-check it has become apparent that the "crafty" check for a leap year performance is nowhere near as good as basic math checks.
Thus I'd consider this to be even more efficient.
var thisDay = new Date();
var thisYear = thisDay.getYear();
var febDays = 28;
if((thisYear % 4 == 0) && (thisYear % 100 != 0) || (thisYear % 400 == 0)){
febDays = 29;
}
var dayCounts = [31,febDays,31,30,31,30,31,31,30,31,30,31];