CodeIgniter Get URL

Question

On one of my pages, I am checking if the user has permissions:

// Validate our user
if ($this->global_model->get_permission() != 'Admin') 
{
    redirect('/permissions/index/'.current_url());
}

On the permissions controller, I am logging where they came from:

$this->global_model->log_data('permission','Invalid Permissions | Referer : ' . $this->uri->segment(3));

Due to the URL having / in it, its giving me http: as URI3.

How can I pass this in the URL but get the whole value?

Kevin · Accepted Answer · 2014-10-17 01:45:01Z

2

You could create a workaround like this to avoid splitting up the URI:

redirect('/permissions/index/' . base64_encode(current_url()) );

Then on the other usage (the parameter next to the method name):

$url = base64_decode($this->uri->segment(3));
$this->global_model->log_data('permission','Invalid Permissions | Referer : ' . $url);

answered Oct 17, 2014 at 1:45

Kevin

41.9k12 gold badges57 silver badges72 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Cool, that worked for me! I had to add an = to $config['permitted_uri_chars'] hope that's not a big issue..

@SBB oh yes i forgot about that, its included in one of the filters of CI, im glad this helped