If...else statement issue with raw_input on Python

Question

I'm currently following Zed Shaw's book on Python, Learn Python the Hard Way and I'm learning about functions. I decided to follow some of the extra credit exercises that went along with the lesson and added an IF ELSE flow statement. This is the code I have below.

print "How much bottles of water do you have?"
water = raw_input("> ")

print "How many pounds of food do you have?" 
food = raw_input("> ")

if food == 1:
    def water_and_food(bottles_of_water, food):
        print "You have %s bottles of water" % bottles_of_water
        print "And %s pound of food" % food

else:
    def water_and_food(bottles_of_water, food):
        print "You have %s bottles of water" % bottles_of_water
        print "And %s pounds of food" % food

water_and_food(water, food)

What I want to do is this. If the user inputs they have 1 pound of food, it will display "You have 1 pound of food" If they input they have 2 pounds of food or more, it will display "You have 2 pounds of food," the difference of pound being singular or plural.

However, if I put 1, it will still display "You have 1 pounds of food," however if I directly assign a number to the variables water and food, it will work.

Narpar1217 · Accepted Answer · 2014-10-19 05:10:22Z

4

The return value of raw_input is a string, but when you check the value of food, you are using an int. As it is, if food == 1 can never be True, so the flow always defaults to the plural form.

You have two options:

if int(food) == 1:

The above code will cast food to an integer type, but will raise an exception if the user does not type a number.

if food == '1':

The above code is checking for the string '1' rather than an integer (note the surrounding quotes).

answered Oct 19, 2014 at 5:10

Narpar1217

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2 Comments

Matt Over a year ago

Thank you so much for your help. He might have mentioned that raw_input was always returning a string, but I might have forgotten. It works fine now, thank you for your help.

user3378649 Over a year ago

@Matt If you find it helpful, accept Narpar1217's answer as a valid answer.

t3h2mas · Accepted Answer · 2014-10-19 05:29:49Z

1

In Python 2.x raw_input returns a string. Looking at your code, you could also use input which returns an integer. I would think that would be the most explicit option using Python2.

Then you can treat food as an int throughout your code by using %d instead of %s. When entering a non int your program would throw an exception.

answered Oct 19, 2014 at 5:29

t3h2mas

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