How pass variables for alternative if -syntax?

Question

 <?php 
 $a=3;
 $dir= '/php/';
?>
 <?php if($a ==3){ ?>
<form action="/php/form.php" method="post">
 <p>Name: <input type="text" name="name" /></p>
 <p>Age: <input type="text" name="age" /></p>
 <p><input type="submit" /></p>
</form>
<?php } ?>

I want to pass $dir in form action ,like action=$dir.form.php. It's possible?

Rakesh Sharma · Accepted Answer · 2014-10-28 06:52:36Z

4

Yes it is possible you need to simply pass $dir to action Try

<form action="<?php echo $dir;?>form.php" method="post">

answered Oct 28, 2014 at 6:52

Rakesh Sharma

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3 Comments

Rakesh Sharma Over a year ago

glad to know it's helpful for you you can accept/upvote helpful answers

Dave Chen Over a year ago

@RakeshSharma There's a time limit until the OP can accept. + if you ask me, +50 for this simple answer is rewarding enough :).

Rakesh Sharma Over a year ago

@DaveChen i know :) i am suggesting only

janenz00 · Accepted Answer · 2014-10-28 06:54:14Z

1

You can embed php tags anywhere in your html code. Rewrite your snippet like this:

<?php 
   $a=3;
   $dir= '/php/';
 ?>
 <?php if($a ==3){ ?>
<form action="<?php echo $dir."form.php" ?>" method="post">
<p>Name: <input type="text" name="name" /></p>
<p>Age: <input type="text" name="age" /></p>
<p><input type="submit" /></p>

answered Oct 28, 2014 at 6:54

janenz00

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Comments

Vidya L · Accepted Answer · 2014-10-28 06:55:03Z

1

Yes it is possible

 <?php 
 $a=3;
 $dir= '/php/';

 if($a ==3){ ?>
   <form action="<?php echo $dir.'form.php'; ?>" method="post">
   <p>Name: <input type="text" name="name" /></p>
   <p>Age: <input type="text" name="age" /></p>
   <p><input type="submit" /></p>
</form>
<?php } ?>

answered Oct 28, 2014 at 6:55

Vidya L

2,3344 gold badges30 silver badges44 bronze badges

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