jquery validation not required with custom method [duplicate]

Question

This regarding the JQuery validation plugin. I have a custom method like this.

$.validator.addMethod("USphoneCheck", function(value, element) {
            var phoneNumberPattern = /^\(?(\d{3})\)?[-]?(\d{3})[-]?(\d{4})$/;
            return phoneNumberPattern.test(value);
        }, "Please enter a valid US phone number.");

This is my function call

 cus_phone: {
                    required: false,
                    minlength: 12,
                    USphoneCheck: true
                },

When I run the code without any value I get "Please enter a valid US phone number" message.

This is not required field, But I want to validate when someone entered a value. Am I doing something wrong? Appreciate your help.

Thanks

inside your function add a condition. if (value !== '') { //do the validation } — vaso123
– vaso123, Commented Oct 28, 2014 at 14:35
You must add "OR" this.optional(element) within your return statement. return this.optional(element) || phoneNumberPattern.test(value) This simply makes it "optional". In other words, if you later wanted the field to be required, simply add required: true to the rule declaration without touching this custom method. See the answer within the duplicate. — Sparky
– Sparky, Commented Nov 2, 2014 at 14:59

user3493928 · Accepted Answer · 2014-10-28 14:36:09Z

0

Blank wouldn't be validated with that regex try adding a if else statement to say if its blank don't run the function or wrap the entire regex in () and place a ? at the end.

(/^\(?(\d{3})\)?[-]?(\d{3})[-]?(\d{4})$/)?

answered Oct 28, 2014 at 14:36

user3493928

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2 Comments

Perera1987 Over a year ago

Thanks for your input. It works. Just wondering is there are any other way to do that through jQuery validation plugin? Thanks again.

user3493928 Over a year ago

I'm not familiar with that plugin, however I did find this for you: stackoverflow.com/questions/17970885/… hope it helps.

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