How to store HTML in php variable

Question

what I would like to do is store the HTML of a site in a php variable so it can be echoed at a certain condition. My PHP code:

<?php
$url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$URL = "http://www.example.com/";
$URL2 = "http://www.example2.com/";
$website1 = ?
$website2 = ?
if($url == $URL) {
    echo $website1;
} else if($url == $URL2) {
    echo $website2;
}
?>

I want this HTML (below) to be stored in $website1
There will also be HTML stored in $website2

<html>
    <head>
        <link rel='stylesheet' type='text/css' media='all' href='css/style.css'>
        <link rel='stylesheet' type='text/css' media='all' href='css/jquery-ui-1.10.4.custom.css'>
        <title>Website #One</title>
        <script type='text/javascript' src='js/jquery-1.9.1.js'></script>
        <script type='text/javascript' src='js/jquery-ui-1.10.4.custom.js'></script>
        <script type='text/javascript' src='js/script.js'></script>
    </head>
    <body>
    <div id='header'></div>
    <div id='menu'>
        <button id='navbtn' class='active btn'>Home</button><button id='navbtn2' class='btn'>Pictures</button><button id='navbtn3' class='btn'>Videos</button><button id='navbtn4' class='btn'>Games</button><button id='navbtn4' class='btn'>About</button><button id='navbtn5' class='btn'>Contact</button>
    </div>
    <div id='content'></div>




    </body>
</html>

How would I be able to achieve this?

You can use file_get_contents pointing to html file.

k.tarkin
– k.tarkin

2014-10-29 11:31:28 +00:00
Commented Oct 29, 2014 at 11:31 — k.tarkin
– k.tarkin, Commented Oct 29, 2014 at 11:31

Praveen Kumar Purushothaman · Accepted Answer · 2014-10-29 11:38:46Z

2

I don't understand what logic you are using, but you can achieve this using the PHP's built in function file_get_contents(). Use this way:

<?php
    $url = "http://".getenv("HTTP_HOST")."/".getenv("REQUEST_URI");
    $URL = "http://www.example.com/";
    $URL2 = "http://www.example2.com/";
    $website1 = file_get_contents($URL);
    $website2 = file_get_contents($URL2);
    if($url == $URL) {
        echo $website1;
    } else if($url == $URL2) {
        echo $website2;
    }
?>

edited Oct 29, 2014 at 11:38

user936965

answered Oct 29, 2014 at 11:33

Praveen Kumar Purushothaman

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2 Comments

ʰᵈˑ Over a year ago

I would add a note regarding allow-url-fopen

Praveen Kumar Purushothaman Over a year ago

@ʰᵈˑWhat's that? What should I add? Feel free to edit my post! Thanks in advance.

FLX · Accepted Answer · 2014-10-29 11:31:30Z

0

You can use file_get_contents(); Or the CURL library http://php.net/manual/fr/book.curl.php

answered Oct 29, 2014 at 11:31

FLX

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3 Comments

ZP18 Over a year ago

hi thanks for quick reply but can you give me an example code because I am not sure what you mean

FLX Over a year ago

You must learn to read a documentation or you will never be a good programmer. This is a really easy function.

user936965 Over a year ago

$website1 = file_get_contents("website1.com"); $website2 = file_get_contents("website2.com");

user936965 · Accepted Answer · 2014-10-29 11:35:54Z

0

Curl is a nice way to do this: http://www.digimantra.com/technology/php/get-data-from-a-url-using-curl-php/

<?php
$url='http://twitter.com/statuses/user_timeline/16387631.json'; //rss link for the twitter timeline
print_r(get_data($url)); //dumps the content, you can manipulate as you wish to

/* gets the data from a URL */

function get_data($url)
{
$ch = curl_init();
$timeout = 5;
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
?>

answered Oct 29, 2014 at 11:35

user936965

Comments

ZP18 · Accepted Answer · 2014-10-29 12:48:16Z

0

Thanks guys I was able to learn from your answers and managed to get it to work here is my final php code:

<?php
$get_url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$url1 = "http://thedag.ga/thedagga/main.php";
$url2 = "http://thedag.ga/zp/zp18.php";
$tdurl1 = "http://thedag.ga/";
$tdurl2 = "http://www.thedag.ga/";
$zpurl1 = "http://zp.thedag.ga/";
$zpurl2 = "http://zp18.thedag.ga/";
$zpurl3 = "http://zp4rker.thedag.ga/";
if($get_url == $tdurl1 || $get_url == $tdurl2) {
    print_r(file_get_contents($url1));
} else if($get_url == $zpurl1 || $get_url == $zpurl2 || $get_url == $zpurl3) {
    print_r(file_get_contents($url2));
}
?>

answered Oct 29, 2014 at 12:48

ZP18

21

Comments

TheMeq · Accepted Answer · 2014-10-29 11:42:30Z

-1

Why not just put both versions in there own PHP file, that is, if it is only some simple one page html, and not an entire website, then the other suggestions would probably be better.

<?php
$url = "http://".getenv("HTTP_HOST")."/".getenv("REQUEST_URI");
$URL = "http://www.example.com/";
$URL2 = "http://www.example2.com/";
if($url == $URL) {
    include 'header1.php';
} else if($url == $URL2) {
    include 'header2.php';
}
?>

edited Oct 29, 2014 at 11:42

answered Oct 29, 2014 at 11:35

TheMeq

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