bash source command and the filename of the script

Question

I have a bash script that will need to be executed using the bash built-in source. But it needs to read its own filename and update PATH based on it. Unfortunately, $0 does not contain the name of the script. So the following does not work.

ABSDIR=$(pwd)/$(dirname "$0")
export PATH="$ABSDIR/Library/Developer/CommandLineTools/usr/bin:$PATH"

Is there a way to get the name of the script file in this context?

source ~/CLTools/Clang-5.0/activate

Cyrus · Accepted Answer · 2014-10-31 11:47:09Z

2

Take a look at:

echo ${BASH_SOURCE[0]}

answered Oct 31, 2014 at 11:47

Cyrus

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1 Comment

fedorqui Over a year ago

What do you mean with "take a look"? Try to expand the answer to make it something more than a comment.

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