Error with function pointer returning a (void *)

Question

I'm getting a compilation error that states " 'foo' declared as function returning a function" because of a line in my program:

typedef void * (* foo)(void *)(int);

where foo is a function pointer to a function that takes a (void *) type and and int and returns a (void *) type. As I understand it, the declaration above is not returning a function, but a pointer. Is the issue with using a typedef in this situation? The only difference between this function pointer and others I've been using is the (void *) argument, so I assume the problem is related to that. I'm using gcc on a linux machine.

Thanks for the help!

Filipe Gonçalves · Accepted Answer · 2014-11-01 21:11:37Z

4

Your declaration is wrong. The error message makes sense, since foo, as you wrote it, is declared to be a type alias for "pointer to function receiving void * and returning a function that receives int and returns void *.

If the function receives a void * and an int, you should have this instead:

typedef void *(*foo)(void *, int);

This essentially translates to "Let foo denote the type pointer to function receiving a void * and an int and returning a void *"

answered Nov 1, 2014 at 21:11

Filipe Gonçalves

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1 Comment

Jesse Ellison Over a year ago

Perfect, thanks! I'm not sure why I thought each argument had to be encapsulated with () instead of separated by a ",".

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