Function not working in python

Question

Newbie in programming. Trying to self-teach using Head First Programming book. I can not get this following code to work;

            def make_smoothie():
                juice = input("What juice would you like?")
                fruit = input("Ok- and how about the fruit?")
                print "Thanks. Lets go!"
                print "Crushing ice..."
                print "Blending the %d" % fruit
                print "Now adding in the %d juice" %juice
                print "Finished! There's your %d and %d smoothie" %(fruit, juice)


            print ("Welcome to smoothie")
            another ="Y"
            while another=="Y":
                make_smoothie()
                another = input ("How about another (Y/N)?")

Keep getting the error that the input for juice or fruit is not defined

see my answer ... its cause that code is meant for python3 but you are using python 2 ... and the user input methods are a little difference — Joran Beasley
– Joran Beasley, Commented Nov 6, 2014 at 1:02
Please mark at least one answer as accepted so person gets credit and so browswer like me know that you aoready have answer. — Terry Jan Reedy
– Terry Jan Reedy, Commented Nov 6, 2014 at 3:36

holybull · Accepted Answer · 2014-11-06 01:12:52Z

1

It works fine for me and I am using Python 2.x. Are you providing numbers for juice and fruit because you use %d for text formatting?

oltjano@baby:~/Desktop/unveil/tests$ python juice.py 
Welcome to smoothie
How about another (Y/N)?"Y"
What juice would you like?1
Ok- and how about the fruit?2
Thanks. Lets go!
Crushing ice...
Blending the 2
Now adding in the 1 juice
Finished! There's your 2 and 1 smoothie
How about another (Y/N)?

edited Nov 6, 2014 at 1:12

answered Nov 6, 2014 at 1:07

holybull

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1 Comment

Joran Beasley Over a year ago

+1 for pointing out that even if he fixes input it will still break on his format string

Joran Beasley · Accepted Answer · 2014-11-06 01:01:04Z

0

just a guess ... if you are using python 2 then use raw_input instead of input ... (in python 2 input will try to evaluate the users input to a python object (integer or variable name, etc) ... raw_input will return the user input as a string)

consider

>>> apple = 555
>>> print input("Enter Fruit:")
Enter Fruit:apple
555 #returns the value of the variable apple ... if that does not exist you get an error
>>> print raw_input("Enter Fruit:")
Enter Fruit:apple
apple #returns the string "apple"

answered Nov 6, 2014 at 1:01

Joran Beasley

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