accessing 2d array, allocated using malloc.

Question

G'day!

So if I declared the array like this:

int *A[5];

and did this:

A[0]=(int*)malloc(sizeof(int)*10);

Can I access/populate via A[0][5] with the square bracket notation?

Sourav Ghosh · Accepted Answer · 2014-11-06 10:13:42Z

1

Yes, you can access A[0][n] as long as that [n] does not run past the allocated memory region.

Maybe it's helpful to remember that in c, the index will be 1 less than the number of memory locations allocated.

answered Nov 6, 2014 at 10:13

Sourav Ghosh

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Some programmer dude · Accepted Answer · 2014-11-06 10:11:55Z

0

For the most parts, arrays and pointers are interchangeable (as arrays decays to pointers), and that includes the syntax to access them. So yes, you can use the array-indexing syntax to access a pointer.

In fact, doing a[x] is equivalent to doing *(a + x).

answered Nov 6, 2014 at 10:11

Some programmer dude

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