Saving numpy array into dictionary using loop

Question

Below is my loop to loop through a bigger array (sortdata), pull out individual columns, and save those into a dictionary based on its iteration in the loop. My problem is that this loop is only looping through and saving just one column. It saves the variabledict[1] array and nothing else. The sortdata array contains four columns (the first two do not have pertinent data so I omitted them in the code). There should be a variabledict[0]. Any help would be greatly appreciated.

datavalues = floating number that pertains to total columns

sortdata = large array I am pulling data from

for k in range(int(datavalues - 2)):
  datavalloop = sortdata[:][0:,k + 2]
  variabledict = {}
  variabledict[k] = datavalloop

You are resetting variabledict to be an empty dict inside the loop, so it goes back to {} every time, and only the final iteration will leave anything stored in the dict. — ely
– ely, Commented Nov 7, 2014 at 16:15

Irshad Bhat · Accepted Answer · 2014-11-07 16:16:34Z

1

Place variabledict = {} outside loop. It is clearing dictionary values to Null on every iteration leaving only values of the last iteration.

answered Nov 7, 2014 at 16:16

Irshad Bhat

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Vincent Beltman · Accepted Answer · 2014-11-07 16:16:48Z

1

Place vaiabledict outside the loop. You are resetting it every time:

variabledict = {}
for k in range(int(datavalues - 2)):
    datavalloop = sortdata[:][0:,k + 2]
    variabledict[k] = datavalloop

answered Nov 7, 2014 at 16:16

Vincent Beltman

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