How can I do string operations in XSLT?

Question

I have the following code block in my xslt;

      <xsl:when test="StatusData/Status/Temperature > 27">
        <td bgcolor="#ffaaaa">              
          <xsl:value-of select="StatusData/Status/Temperature" />              
        </td>
      </xsl:when>

But as you might guess when the value is 34,5 instead of 34.5 it is recognised as a string which makes integer comparison not possible. I thought replacing , with . would be solution that needs a char replace. My question is how I can do this or It would be great to know more about string operations in XSLT...

Tomalak · Accepted Answer · 2008-11-06 10:05:37Z

8

There is a translate() function in XPath:

test="translate(StatusData/Status/Temperature, ",", ".") > 27"

Additionally you should make use of the number function, which converts it's argument to a number (or NaN, if that fails):

test="number(translate(StatusData/Status/Temperature, ",", ".")) > 27.0"

See the documentation for translate() and the documentation for number() at w3.org.

edited Nov 6, 2008 at 10:05

answered Nov 6, 2008 at 9:58

Tomalak

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Comments

Oleks · Accepted Answer · 2012-01-23 07:27:50Z

0

Thanx a lot.

it works but with one simple modification:

test="number(translate(StatusData/Status/Temperature, ',', '.')) > 27.0"

by the way it is not about XSLT it is about XPath :) good to learn...

edited Jan 23, 2012 at 7:27

Oleks

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answered Nov 6, 2008 at 10:07

yusuf

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Comments

Oleks · Accepted Answer · 2012-01-23 07:28:05Z

0

In XSL 2 you can also use the full-fledged replace() which even supports regex patterns.

edited Jan 23, 2012 at 7:28

Oleks

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answered Jan 11, 2009 at 17:16

Egor

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