Javascript regexp validation not working

Question

I am trying to get my regexp working but I am not having much luck.

I would like to check whether the input string is 6 numbers and 1 character (123123A), no spaces, no dashes. My regex doesn't match even though I think I am entering a valid string.

Could anyone please point me where my issue is?

var userString = "123123A";
if( /^d{6}[a-zA-Z]{1}$/.test(userString) ){
  alert("Correct format");              
}
else{
  alert("Incorrect format");                    
}

put the regexp on the input as a pattern attrib, which works without JS and helps AT. — dandavis
– dandavis, Commented Nov 10, 2014 at 21:04
@BustedSanta - I just edited your question to show you how to ask this sort of question in SO. You want to give a really succinct working example, and keep your explanation centered around the actual problem you're having. — smathy
– smathy, Commented Nov 11, 2014 at 1:45
@smathy - thanks for the tip. I will try to do a better job describing my question the next time. — BustedSanta
– BustedSanta, Commented Nov 11, 2014 at 2:35

hwnd · Accepted Answer · 2014-11-10 21:05:25Z

3

For one, your regular expression syntax is incorrect, you want to use the token \d to match digits instead of matching the literal character d six times. You can also drop {1} from your character class, it is not necessary to use here.

if (/^\d{6}[a-zA-Z]$/.test(userString)) { ...

edited Nov 10, 2014 at 21:05

answered Nov 10, 2014 at 20:58

hwnd

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1 Comment

BustedSanta Over a year ago

thanks for the clarification. You answer has answered and resolved my issue.

Garcia Hurtado · Accepted Answer · 2014-11-10 21:01:06Z

1

You are not checking the value of the input element:

var userString = document.getElementById("username");

Should be

var userString = document.getElementById("username").value;

Also, like hwnd pointed out, you are missing the backslash in the pattern:

/^\d{6}[a-zA-Z]$/

answered Nov 10, 2014 at 21:01

Garcia Hurtado

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