How to get Current User Information using parse.com android

Question

I am working on android for parse.com. I have successfully logged in and signed up with my credentials and data is also uploading in my parse.com tables. Code snippet for login is given below:

loginbutton.setOnClickListener(new OnClickListener() {

            public void onClick(View arg0) {
                // Retrieve the text entered from the EditText
                usernametxt = username.getText().toString();
                passwordtxt = password.getText().toString();

                // Send data to Parse.com for verification
                ParseUser.logInInBackground(usernametxt, passwordtxt,
                        new LogInCallback() {
                            public void done(ParseUser user, ParseException e) {
                                if (user != null) {
                                    // If user exist and authenticated, send user to Welcome.class
                                    Intent intent = new Intent(
                                            LoginSignupActivity.this,
                                            Welcome.class);
                                    startActivity(intent);
                                    Toast.makeText(getApplicationContext(),
                                            "Successfully Logged in",
                                            Toast.LENGTH_LONG).show();
                                    finish();
                                } else {
                                    Toast.makeText(
                                            getApplicationContext(),
                                            "No such user exist, please signup",
                                            Toast.LENGTH_LONG).show();
                                }
                            }
                        });
            }
        });

Now i need to get the information of current user, kindly mention me the method or changing which i have to do to get the information of current user.

Thanks in advance!

Kevin Haube · Accepted Answer · 2014-11-13 08:53:05Z

Calling things like user.getObjectId(); or user.getString("username"); is how you get information from the ParseObject.

loginbutton.setOnClickListener(new OnClickListener() {

            public void onClick(View arg0) {
                // Retrieve the text entered from the EditText
                usernametxt = username.getText().toString();
                passwordtxt = password.getText().toString();

                // Send data to Parse.com for verification
                ParseUser.logInInBackground(usernametxt, passwordtxt,
                        new LogInCallback() {
                            public void done(ParseUser user, ParseException e) {
                                if (user != null) {
                                    // If user exist and authenticated, send user to Welcome.class

                                    String username = user.getString("username");
                                    String userId = user.getObjectId();

                                    Intent intent = new Intent(
                                            LoginSignupActivity.this,
                                            Welcome.class);
                                    startActivity(intent);
                                    Toast.makeText(getApplicationContext(),
                                            "Successfully Logged in",
                                            Toast.LENGTH_LONG).show();
                                    finish();
                                } else {
                                    Toast.makeText(
                                            getApplicationContext(),
                                            "No such user exist, please signup",
                                            Toast.LENGTH_LONG).show();
                                }
                            }
                        });
            }
        });

Huabe by using user.getString() it is giving me null values and can't return my values from server

Pasang Sherpa · Accepted Answer · 2014-11-13 08:55:44Z

2

Once the user is authenticated, open up new activity and you can access current user by using the static method getCurrentUser.

ParseUser currentUser = ParseUser.getCurrentUser();
if (currentUser != null) {
  // do stuff with the user
} else {
  // show the signup or login screen
}

answered Nov 13, 2014 at 8:55

Pasang Sherpa

2741 silver badge3 bronze badges

3 Comments

Usman Khan Over a year ago

Thanks @Pasang Sherpa for your comment. Now i need to get the information from my current User. How to get user information like the information which i have pass in parse.com server

Pasang Sherpa Over a year ago

currentUser.getString('username'); currentUser.getString('firstName');

Usman Khan Over a year ago

it is giving me NULL values. Can't return values from server.

Sami Khan · Accepted Answer · 2015-10-20 10:47:20Z

1

ParseUser currentUser = ParseUser.getCurrentUser();
            currentUser.getUsername();
            newTable.put("user_name",currentUser );

This is how you can get a user information in your other table (newTable). Let me know if it helps. :)

answered Oct 20, 2015 at 10:47

Sami Khan

313 bronze badges

Comments

Miah G. · Accepted Answer · 2020-04-13 21:08:04Z

1

With this I got the user info.

ParseUser currentUser = ParseUser.getCurrentUser();
if (currentUser != null){
   String email = currentUser.getEmail();
   String username = currentUser.getUsername();
   String objectID = currentUser.getObjectId();
} else {
  Toast.makeText(getApplicationContext(), "the user does not exist!",Toast.LENGTH_SHORT).show();
}

answered Apr 13, 2020 at 21:08

Miah G.

1491 silver badge7 bronze badges

Comments

Paul Muriu · Accepted Answer · 2016-06-10 22:58:59Z

0

ParseUser currentUser = ParseUser.getCurrentUser();
String currentUserString = String.valueOf(currentUser.getUsername());
newTable.put("user_name",currentUserString);

For some reason I'm not sure about, you need to cast currentUser to String.

edited Jun 10, 2016 at 22:58

answered Jun 10, 2016 at 22:51

Paul Muriu

12 bronze badges

1 Comment

grochmal Over a year ago

Please do not post answers that do not explain what they do, especially on questions that are old. Someone that finds this question will not benefit from your answer in any manner.

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