parsing XML in Python

Question

I have an XML that I would like to parse then send the result into a txt file.

The XML file is build from blocks like this one :

<rpc-reply message-id="12"
xmlns="urn:ietf:params:xml:ns:netconf:base:1.0">
<user-stats>
<allocated-user-count>10</allocated-user-count>
<current-user-count>3</current-user-count>
<max-active-user-count-24hrs>2</max-active-usercount-
24hrs>
<min-active-user-count-24hrs>0</min-active-usercount-
24hrs>
</user-stats>
</rpc-reply>

All the blocks will start with and and with

I would like to remove all the tags and get the results by line and copy them in a text file. For example :

allocated user count <tab> current-user-count <tab> max-user-count
    100 <tab> 1<tab> 2<tab>
    100 <tab> 0<tab> 2<tab> (info taken from the second RPC block)

etc

Is there any way I can do this?

Anshul Goyal · Accepted Answer · 2014-11-14 17:32:36Z

1

You can use the xmltodict module for this.

You will need to install it using

pip install xmltodict

Once you've it, just do

import xmltodict
data = xmltodict.parse(xmldata)

This will give you an early traversable python dict, which you can then use to get the values you want.

answered Nov 14, 2014 at 17:32

Anshul Goyal

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Qwertronix · Accepted Answer · 2014-11-14 17:38:13Z

0

Yes, there are ways you can do this.

The most accessible would be to use the XML Processing Modules, included in Python's standard library, to read the XML, and then use a text file object to output to the text file after doing your processing.

answered Nov 14, 2014 at 17:38

Qwertronix

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