php decode JSON get values

Question

I'm trying to decode JSON format

What I am sending is:

{
"id": 123,
"name": "John",
“surname”: “Smith”,
“department”: 3
}

I am sending POST with data via Postman, in the picture.
So, this is the data I want to decode:

"data_serever_received": "{ \"id\": 123, \"name\": \"john\", “surname”: “Smith”, “department”: 3 }"

enter image description here

I tried

$this->input->data["id"]

but it is not working.

How can I get the id, name, surname and etc. values?

I suggest you also use Content-Type: application/json to make the process better. — Idris
– Idris, Commented Nov 15, 2014 at 17:14
why you are sending “surname” , “Smith” and “department” in ” instead of " ? — fortune
– fortune, Commented Nov 15, 2014 at 17:53

Quentin · Accepted Answer · 2014-11-15 17:54:24Z

3

Your JSON is invalid “ and ” are not ".

(Zoom in with your browser if you can't see the difference).

You need to start with valid JSON before you can parse it.

answered Nov 15, 2014 at 17:54

Quentin

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silversunhunter · Accepted Answer · 2014-11-15 17:45:14Z

0

You can use json_decode to make it an array.

$json_array = json_decode($json_object);//$json_object will need to contain your json string.

then you can access like this:

echo $json_array["data"][“surname”];

PHP Doc on json_decode: http://php.net/manual/en/function.json-decode.php

edited Nov 15, 2014 at 17:45

answered Nov 15, 2014 at 17:12

silversunhunter

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5 Comments

Zelí Over a year ago

Thanks for the answer, but when i do that i get null in $json_array

silversunhunter Over a year ago

what is the $_POST variable that the json string is in?

Zelí Over a year ago

$_POST looks like this: "POST": { "user": "{ \"id\": 123, \"name\": \"john\", “surname”: “Smith”, “department”: 3 }" }

silversunhunter Over a year ago

Ok, and you are doing json_decode($_POST['your_json_string'])?

silversunhunter Over a year ago

Will you add your complete code to the question please.

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