how to save django object using dictionary?

Question

is there a way that I can save the model by using dictionary

for e.g. this is working fine,

p1 = Poll.objects.get(pk=1)

p1.name = 'poll2'
p1.descirption = 'poll2 description'

p1.save()

but what if I have dictionary like { 'name': 'poll2', 'description: 'poll2 description' }

is there a simple way to save the such dictionary direct to Poll

Daniel Roseman · Accepted Answer · 2010-04-23 08:07:22Z

34

drmegahertz's solution works if you're creating a new object from scratch. In your example, though, you seem to want to update an existing object. You do this by accessing the __dict__ attribute that every Python object has:

p1.__dict__.update(mydatadict)
p1.save()

answered Apr 23, 2010 at 8:07

Daniel Roseman

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1 Comment

floer32 Over a year ago

This can be very useful for upholding the DRY principle while doing tricky stuff on the save() method of ModelForm. For example, I have a a form that copies cleaned_data to a new dictionary, then deletes certain fields from it -- because values from other fields make them irrelevant or contradictory -- then saves only the remaining fields in that dictionary onto the instance (and the instance is an object that has already been initialized).

score 30 · Accepted Answer · 2010-04-23 07:50:46Z

30

You could unwrap the dictionary, making its keys and values act like named arguments:

data_dict = {'name': 'foo', 'description': 'bar'}

 # This becomes Poll(name='foo', description='bar')
 p = Poll(**data_dict)
 ...
 p.save()

edited Apr 23, 2010 at 7:50

answered Apr 23, 2010 at 7:40

user257858

Comments

Слава · Accepted Answer · 2019-12-26 17:12:47Z

2

I find only this variant worked for me clear. Also in this case all Signals will be triggered properly

p1 = Poll.objects.get(pk=1)
values = { 'name': 'poll2', 'description': 'poll2 description' }        
for field, value in values.items():
    if hasattr(p1, field):
        setattr(p1, field, value)
p1.save()

answered Dec 26, 2019 at 17:12

Слава

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Comments

toast38coza · Accepted Answer · 2021-02-01 21:39:52Z

1

You could achieve this by using update on a filterset:

e.g.:

data = { 'name': 'poll2', 'description: 'poll2 description' }
p1 = Poll.objects.filter(pk=1)
p1.update(**data)

Notes:

be aware that .update does not trigger signals
You may want to put a check in there to make sure that only 1 result is returned before updating (just to be on the safe side). e.g.: if p1.count() == 1: ...
This may be a preferable option to using __ methods such as __dict__.

answered Feb 1, 2021 at 21:39

toast38coza

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