Filtering XML based using xslt

Question

I have an xml and want to filter out sections that I do not need. Here is the xml & respective expected out put,

    <CD>
  <RT></RT>
  <author></author>
  <component>
    <structurebody>
      <component>
        <section>
          <templateid root = "1" />
        </section>
        </component>
        <component>
          <section>
            <templateid root = "2" />
          </section>
        </component>
        <component>
          <section>
            <templateid root = "3" />
          </section>
          </component>
        </structurebody>
    </component>
  </CD>

I want the output to contain sections with template id's 1 and 3 not 2. I am trying the following xslt but it does not work. It outputs everything. Not sure what is wrong

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

 <xsl:template match="@*|node()">
        <xsl:copy>
          <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
  </xsl:template>

  <xsl:template match="/component/structuredBody/component/section/templateId[not(@root = '1' or @root = '3')]" />
</xsl:stylesheet>

Can anyone let me know where am I making a mistake? Appreciate your help.

Tim C · Accepted Answer · 2014-11-18 16:28:40Z

1

Try this...

<xsl:template match="/CD/component/structuredBody/component/section[templateId[not(@root = '1' or @root = '3')]]" />

Note this initial /CD in the xpath. Also, note this matches section not templateId (assuming you wish to remove the section element, not just the child template.

Actually, you can just simplify it to this. Specifying the whole hierarchy is not strictly necessary here.

<xsl:template match="section[templateId[not(@root = '1' or @root = '3')]]" />

answered Nov 18, 2014 at 16:28

Tim C

70.7k14 gold badges77 silver badges94 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Filtering XML based using xslt

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related