Concatenation syntax error using baseurl()

Question

echo '<br /><a href=''.base_url().'home/do_logout'>Logout Fool!</a>';

What did I missed out in above concatenation?

I got this error

Message: syntax error, unexpected ''.base_url()."home/do_logout'' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';'

Hope my answer can help you out! Also if your interested to take a tour about SO see: stackoverflow.com/tour (takes less then 1 min and show's how it all works with voting and so on) — Rizier123
– Rizier123, Commented Nov 20, 2014 at 3:09
You need to understand also, the difference in using double quotes vs single quotes. Double quotes PHP will try to parse variables, single it will not. — ratiorick
– ratiorick, Commented Nov 20, 2014 at 16:22

Rizier123 · Accepted Answer · 2014-11-20 02:15:19Z

2

This should work for you:

echo "<br /><a href='" . base_url() . "home/do_logout'>Logout Fool!</a>";

answered Nov 20, 2014 at 2:15

Rizier123

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ratiorick · Accepted Answer · 2014-11-20 03:30:24Z

1

Using mixed mode processing looks cleaner some of the time - and easier to maintain. Close and reopen your php tags when you want to switch to just html

<br>
<a href="<?php echo base_url(); ?>/do_logout">Logout Fool!</a>

answered Nov 20, 2014 at 3:30

ratiorick

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