Parse json string into scala case class in java

Question

I have a small spring(mvc) web application. This application has dependency on one scala module, which has a case class MessageCommand. I want to convert the JSON String into MessageCommand Case class using Jackson.

Is this possible?

I am using Spring 4, Jackson-asl 1.9, Scala 2.11 Case class.

Jatin · Accepted Answer · 2014-11-24 07:03:52Z

2

Well you can. But you need to tweak some things in case class:

case class Message(@BeanProperty var num:Int, @BeanProperty var name:String){
    def this() = this(-1,null)
}

import org.codehaus.jackson.map.ObjectMapper
import scala.beans.BeanProperty

val mapper = new ObjectMapper
val json = """{"num":1,"name":"Di Caprio"}"""

scala> val user = mapper.readValue(json, classOf[Message])
user: Message = Message(1,Di Caprio)

If you cannot tweak the case class, then it gets a bit difficult and untidy

answered Nov 24, 2014 at 7:03

Jatin

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6 Comments

Yadu Krishnan Over a year ago

What s the way if I can not edit the scala class? Do I need to write a simple java class and then set the values into the case class from the java class manually?

Jatin Over a year ago

I googled and found this: github.com/mesosphere/jackson-case-class-module Not sure on how good it is.

Yadu Krishnan Over a year ago

I have to do this in Java, not scala. I mean I need to parse a string in java and convert as Scala Case class

Yadu Krishnan Over a year ago

I applied the answer you have provided and changed the scala code. that is working fine.

Jatin Over a year ago

If you are doing it in Java. Things still remain the same: ObjectMapper m = new ObjectMapper(); m.readValue(json, Message.class) :)

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