get node and value if it's not null using Xslt

Question

I have a requierement as below:

if i give input as :

<?xml version="1.0"?>
<new:NewAddressData xmlns:new="http://www.example.org/NewAddress">
  <new:NewStreet></new:NewStreet>
  <new:NewArea>Area_1</new:NewArea>
  <new:NewState></new:NewState>
</new:NewAddressData>

Output should be:

<new:NewArea>Area_1</new:NewArea>

Actually Iam new bee to XSLT but I read some basics and tried below code :

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">        
    <xsl:copy>
        <xsl:choose>
            <xsl:when test="@*|node() != ''">  
      <xsl:value-of select="." disable-output-escaping="yes" />
            </xsl:when>                        
            <xsl:otherwise>
                <xsl:apply-templates  select="@*|node()"/>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:copy>
</xsl:template>

for this I am getting output as :

<new:NewAddressData xmlns:new="http://www.example.org/NewAddress">Area_1</new:NewAddressData>

where expected value should be like :

<new:NewArea>Area_1</new:NewArea>

So how can I achieve this using XSLT 1.0

Thanks in advance

What you did here is: You dropped a requirement onto this website, in hopes someone would give you the codes. That's not how this website works. Please show your efforts and explain the specific problems you have. We are not a free programming service. — Tomalak
– Tomalak, Commented Nov 24, 2014 at 14:54
Input is not standard XML, it is not well formed, place your XSLT, what you have tried to get the result. — Rudramuni TP
– Rudramuni TP, Commented Nov 24, 2014 at 15:31
Hi @Tomalak thanks for the response. please let me know if any other info required. — Uday Shankar
– Uday Shankar, Commented Nov 24, 2014 at 19:36
Hi @RudramuniTP thanks for the response actually i had placed the input xml which i am using. let me know if any further info required. — Uday Shankar
– Uday Shankar, Commented Nov 24, 2014 at 19:38
@Uday, your are welcome. U asked a nice question, in future along post place complete info like 'input XML', XSLT, and required result. — Rudramuni TP
– Rudramuni TP, Commented Nov 25, 2014 at 9:27

Daniel Haley · Accepted Answer · 2014-11-24 19:50:00Z

1

You could do something like this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output indent="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:template match="*[text()]">
        <xsl:copy-of select="."/>
    </xsl:template>

</xsl:stylesheet>

Depending on input, like if there was more than one element that contained text, this might result in output that is not well formed.

answered Nov 24, 2014 at 19:50

Daniel Haley

53.1k7 gold badges75 silver badges97 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Rudramuni TP Over a year ago

Perfect code, it is working for complex elements too.

Uday Shankar Over a year ago

Hi @Daniel, thanks for the helping hand. code is working as expected.

Tim C · Accepted Answer · 2014-11-25 08:50:18Z

0

It looks like you have read about the XSLT Identity Template, which is good!

 <xsl:template match="@*|node()">
   <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
   </xsl:copy>
</xsl:template>

On its own, this will copy across all nodes unchanged (such as your NewArea element), so you need to then write templates for the things you do want to change. In this case, it looks like you want to remove elements that don't have non-empty text nodes as children.

 <xsl:template match="*[not(text()[normalize-space()])]">

Try this XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="xml" indent="yes"/>

   <xsl:template match="@*|node()">
      <xsl:copy>
         <xsl:apply-templates select="@*|node()"/>
      </xsl:copy>
   </xsl:template>

   <xsl:template match="*[not(text()[normalize-space()])]">
      <xsl:apply-templates />
   </xsl:template>
</xsl:stylesheet>

This would output the following

 <new:NewArea xmlns:new="http://www.example.org/NewAddress">Area_1</new:NewArea>

The namespace is necessary here. You can not output an element with a prefix without also declaring the namespace associated with it.

edited Nov 25, 2014 at 8:50

answered Nov 24, 2014 at 21:19

Tim C

70.7k14 gold badges77 silver badges94 bronze badges

1 Comment

Uday Shankar Over a year ago

Hi @Tim, thanks for the helping hand. code is working as expected.

Collectives™ on Stack Overflow

get node and value if it's not null using Xslt

2 Answers 2

2 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related