How to put an array from a method in an array in the calling method?

Question

I want to know if (and how) I can put my reversed array from my method ArrayReverse in the array result(where the ?????????? are) in my main method.
The code should print out "Funktioniert"

My code:

public class blubb {
    public static void main(String[] args) {
        char[] array = {'t', 'r', 'e', 'i', 'n', 'o', 'i', 't', 'k', 'n', 'u', 'F'};
        char[] result= new char[??????????];

        result=ArrayReversed(array);

        for (int i = 0; i < ergebnis.length; i++) {
            System.out.println(ergebnis[i]);

       }
    }

    public static char[] ArrayReversed(char[] arr) {
        char [] blubb= new char[arr.length];
        for (int i = arr.length-1; i >=0; i--) {
           blubb[i]=arr[i];
        }
        return blubb;

    }
}

P.S. psvm is not an abbreviation commonly used to refer to public static void main... please don't use it. — ajb
– ajb, Commented Nov 25, 2014 at 21:53

Ensar Hatipoglu · Accepted Answer · 2014-11-25 21:53:31Z

1

All the answers are correct, you just assign the return result to your variable:

char[] result = ArrayReversed(array);

The reason you think it doesn't work is because of this line in your code:

for (int i = arr.length-1; i >=0; i--) {
    blubb[i] = arr[i];
}

This is not going to revers the array. You are just copying same characters from one array to another, into same positions. Perhaps you are looking for something like:

for(int i=0; i<arr.length; i++) {
    blubb[i] = arr[arr.length-1-i];
}

answered Nov 25, 2014 at 21:53

Ensar Hatipoglu

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Comments

boxsome · Accepted Answer · 2014-11-25 21:45:50Z

Basically, you don't need to initialize your "result" array. Just set it to the returned value of ArrayReversed. Then in your for loop, you actually want to use the result array and iterate/print out its values.

public class blubb {
    public static void main(String[] args) {
        char[] array = {'t', 'r', 'e', 'i', 'n', 'o', 'i', 't', 'k', 'n', 'u', 'F'};
        char[] result;

        result=ArrayReversed(array);

        for (int i = 0; i < result.length; i++) {
            System.out.println(result[i]);

       }
    }

    public static char[] ArrayReversed(char[] arr) {
        char [] blubb= new char[arr.length];
        for (int i = arr.length-1; i >=0; i--) {
           blubb[i]=arr[i];
        }
        return blubb;

    }
}

austin wernli · Accepted Answer · 2014-11-25 21:56:59Z

0

why not just do char[] result = ArrayReversed(array);

Also, your method ArrayReversed is wrong. It should be like this.

public static char[] ArrayReversed(char[] arr) {
    char [] blubb= new char[arr.length];
    for (int i = arr.length-1; i >=0; i--) {
       blubb[i]=arr[arr.length-1-i];
    }
    return blubb;

}

edited Nov 25, 2014 at 21:56

answered Nov 25, 2014 at 21:45

austin wernli

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3 Comments

Saboteur Over a year ago

doesn't work. it doesn't outprint "Funktioniert" it prints the array "treinoitknuf" out....

austin wernli Over a year ago

well that is because your reverse array is wrong heh

ajb Over a year ago

@Saboteur blubb[i]=arr[i] just makes a copy of the array, since you're copying every character into the same position.

animageofmine · Accepted Answer · 2014-11-25 22:00:34Z

0

You don't need to allocate new memory to result. Something like this should work (note some changes I made to your code since there was one more bug in your code)

public class blubb {
    public static void main(String[] args) {
        char[] array = {'t', 'r', 'e', 'i', 'n', 'o', 'i', 't', 'k', 'n', 'u', 'F'};
        char[] result= ArrayReversed(array);

        System.out.println(result);           
    }

    public static char[] ArrayReversed(char[] arr) {
        char [] blubb= new char[arr.length];
        for (int i = arr.length-1, j = 0; i >=0; i--, j++) {
           blubb[i]=arr[j];
        }
        return blubb;
    }
}

edited Nov 25, 2014 at 22:00

answered Nov 25, 2014 at 21:54

animageofmine

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