String variable as input for functions

Question

I have a function

getText();

it works this way

getText("This is a really nice text");

but it does not work this way

std:string myString = "Also a nice text";
getText(myString);

Why?

you didn't say how is getText declared, I guess it is void getText(const char*) — Piotr Skotnicki
– Piotr Skotnicki, Commented Nov 26, 2014 at 9:33
"I have a function getText();" - that's not a function. that's a function call. where's your function? or at least, the signature... — Karoly Horvath
– Karoly Horvath, Commented Nov 26, 2014 at 9:34
Maybe just a typo, but the namespace separator is :: not : — Balázs Édes
– Balázs Édes, Commented Nov 26, 2014 at 9:41

tnishada · Accepted Answer · 2014-11-26 09:39:37Z

1

I think your function declaration may be like this => " getText(char *parameter)"

if your function declaration is like this => " getText(std::string parameter) "

it should be working

answered Nov 26, 2014 at 9:39

tnishada

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